Interview Question 3538

Created by admin on Sat, 17/11/2012 - 12:23
Explanation: 
p is pointing to character '\n'. str1 is pointing to character 'a' ++*p. "p is pointing to '\n' and that is incremented by one." the ASCII value of '\n' is 10, which is then incremented to 11. The value of ++*p is 11. ++*str1, str1 is pointing to 'a' that is incremented by 1 and it becomes 'b'. ASCII value of 'b' is 98. Now performing (11 + 98 – 32), we get 77("M");So we get the output 77 :: "M" (Ascii is 77)..
Question: 

#include main()
{
char s[]={'a','b','c','\n','c','\0'};
char *p,*str,*str1; p=&s[3]; str=p;
str1=s; printf("%d",++*p + ++*str1-32);
}

Language: 
C
Answer: 

77